<正> 对于远交联络空间与度量联络空间之同质对应问题,吾人在前一文[1]内利用各该空间之曲率张量,已完全予以解决。在该文内解析的证明中,系应用(?)于微分方程式系之某一熟知定理[2].本文之作,意欲避免该项定理,而以曲率张(?)及共共变微分所满足之某种互等式代之。

An analytic proof for the equivalence of two affine spaces and twometric spaces in terms of their curvature tensors was given in a previouspaper[1]by making use of a known theorem about differential equationsof mixed system.[2]In the present note we shall give a proof for thesame purpose without any application of the theorem just mentioned,instead of which some identities[3][4]in curvature tensor and its covariantderivatives are used.